C programming: Does scanf not read values 0 and 1 as intended as integers? -

i trying sum of multiples of 2 values.

i used scanf request integer value twice user.

in code , algorithm created works intended except when user input value of 0 and/or 1.

i want computer able accept value of 0 , result in total of 0 , when accepting 1 total sum of 1 0 gives me odd crash , 1 gives me big value.

/*multiples of 3 or 5: 3,5,6,9; sum 23*/  #include <stdio.h>  int main() {     int value,value2,limit = 1000;     int i,divi,sum = 0;       /*read user input first value*/      scanf("%d",&value);      /*get sum of multiples of value*/     for(i = value;i < limit;){         sum = sum + i;         = + value;     }     printf("%d\n",sum);     printf("done %d\n",value);      /*read user input second value*/     scanf("%d",&value2);     /*get sum of multiples of value2*/     for(i = value2;i < limit;){         divi = i%value;         if((divi)==0){             = + value2;         }         else         {             sum = sum + i;             = + value2;         }      }     printf("%d\n",sum);     printf("done %d\n",value2);     return 0; } 

the for loop intended count things off. don't need to, it's more readable. i'll later.

for first loop, have:

for(i = value;i < limit;){     sum = sum + i;     = + value; } 

this...

• sets initial value of i, value. is...a little unorthodox , might causing confusion.
• each iteration, test i against limit.
• increments sum ever-increasing value of i.
• increases value of i value.

the problem see that, when value zero, i never changes.

there's oddity sum doesn't appear multiples. if value 1, sum 0, 1, 3, 6, 10, 15...triangular numbers. doesn't sound want.

instead, think want use for loop intent, counting, , increase sum repeatedly. like:

for(i = 0;i < limit;i++){     sum = sum + value; } 

that says add value sum, limit times.

if did need triangular numbers, may want introduce supplemental variable. if counting isn't want, might want while loop, instead, readability, like:

while (sum < limit){     sum = sum + value;  /* or whatever need, here */ } 

but test input value make sure it's not 0. no matter how many zeroes add, they're not going bigger limit...well, unless limit negative.