c++ - Tic-Tac-Toe Program -

i'm trying create tic-tac-toe program determine if given playing board won "x" "o" or tie.

obviously know games won who, how can program check that?

int check(int board[3][3]) { //i've tried putting code here, nothing successful.    return 0; }  int main() { // three-dimensional array, 3 games of two-dimensional // boards; concern two-dimensional boards int games[3][3][3] = {      {           { -1,  0,  1 },  //o_x         {  0,  1, -1 },  //_xo         {  1, -1,  0 }   //xox     },     {           {  0,  1,  1 },  //_xx         { -1, -1, -1 },  //ooo         {  1,  1,  0 }   //xx_     },     {           {  1,  1, -1 }, //xxo         { -1, -1,  1 }, //oox         {  1,  1, -1 }  //xxo      } };  (int game = 0; game < 3; game++) {     if (check(games[game]) == 1) {         cout << "player x wins game " << game + 1 << endl;     } else if (check(games[game]) == -1) {         cout << "player o wins game " << game + 1 << endl;     } else {         cout << "game " << game + 1 << " cat game" << endl;     } }      return 0; } 

this should work:

int check(int board[3][3]) {      int winner = 0;       // check line      for( int i=0; i<3; ++i )           {                 if( board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != 0)                     winner = board[i][0];             }       // check column      for( int i=0; i<3; ++i )           {                 if( board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i] != 0 )                     winner = board[0][i];             }       // check diagonal      if( board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != 0)           winner = board[1][1];       if( board[2][1] == board[1][1] && board[1][1] == board[0][2] && board[1][1] != 0)           winner = board[1][1];  return winner; }