javascript - changing style based on content -


i have html

<div class="common"> <p class="special">     <p class="child">test1</p> </p> <p class="special">     <p class="child">test2</p> </p></div>

as see have 2 paragraphs same style different content, want change , style of paragraph content contains "test1", wrote this

$(".common").each(function () { if ($(this).find('.special').find('.child').text() == "test1") {     $(this).find('.special').find('.child').css('background','red'); }});

but style applied both paragraphs, there solution solve in javascript/jquery

your html invalid - p element cannot contain p element

<div class="common">     <div class="special">         <p class="child">test1</p>     </div>     <div class="special">         <p class="child">test2</p>     </div> </div>

then

$(".common .special .child").each(function () {     if ($(this).text() == "test1") {         $(this).css('background', 'red');     } });

demo: fiddle

you code find first .special .child elementinside each.commonand if text matches test case applies styles all.special .childelements within the.common`


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