android - Unable to resolve Phone Gap [error] cmd: Command failed with exit code ENOENT 3 -
unable run sencha/phonegap application in android.. getting exception "cmd: command failed exit code enoent 3" here version installed..
d:\testapp>sencha -version sencha cmd v4.0.1.45 [err] no such property : version @ com.sencha.cli.abstractcommand$properties.getproperty(abstractcommand.ja va:417) @ com.sencha.cli.abstractcommand.parseconfigparam(abstractcommand.java:441 ) @ com.sencha.cli.abstractcommand.processconfigparam(abstractcommand.java:4 91) @ com.sencha.cli.abstractcommand.configure(abstractcommand.java:114) @ com.sencha.command.sencha.main(sencha.java:136) d:\testapp>phonegap -version 3.4.0-0.19.7 d:\testapp>cordova -version 3.4.0-0.1.3 d:\testapp>ant -version apache ant(tm) version 1.9.3 compiled on december 23 2013 d:\testapp>phonegap run android [phonegap] detecting android sdk environment... [phonegap] using local environment [phonegap] adding android platform... [error] cmd: command failed exit code enoent d:\testapp>phonegap build android [phonegap] detecting android sdk environment... [phonegap] using local environment [phonegap] adding android platform... [error] cmd: command failed exit code enoent in advance
check following steps:
cordova create testapp com.example.testapp testappcd testappcordova platform add androidcordova build android
after should copy project , paste immediate www folder of cordova project. , run
cordova run android
from above snippet seems have cordova installed in system. nb: above cli steps cordova versions 3.x
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