python - decorator - Setting a wrapped functions argument names and values -

is possible give wrapped function arg , kwargs names of function wrapping? need because decorators applied later use arg names of underlying function.

def wrapper(func):     def wrapped(<func args , kwargs names , values>):         return func(*args, **kwargs) 

so if func been passed in foo(x,y=3), returned wrapped function have signature wrapped(x, y=3) instead of usual wrapped(*args, **kwargs).

--edit--

just found duplicate of preserving signatures of decorated functions . answers anyway

i'm not sure understand question, isn't expect ?

>>> def wrapper(func):     def wrapped(*args, **kwargs):         print args, kwargs         return func(*args, **kwargs)     return wrapped  >>> @wrapper def foo(x, y=3):     return x + y  >>> foo(3) (3,) {} 6 >>> foo(3, 5) (3, 5) {} 8 >>> foo(3, y=5) (3,) {'y': 5} 8