shell - capture-specific-columns and mask the column -


i trying write script capture , mask specific column.i need have 4 column clear text , mask in output file .i not sure how mask same column

pls me in rewriting below command or new command 

input.txt --------- aa | bb | cc | 123456  output.txt --------- bb | 123456 | 12xx56

script wrote 

cat input.txt | nawk -f '|' '{print $2  "|" $4 "|" $4} >output.txt 

nawk -f '|' '{print $2  "|" $4 "|" substr($4, 1,3) "xx" substr($4,6,2)}' input.txt > output.txt

output

bb | 123456| 12xx56

assuming don't need leading , trailing spaces, make it

nawk -f '|' '{gsub(/  */, "", $0);print $2  "|" $4 "|" substr($4, 1,2) "xx" substr($4,5,2)}' input.txt > output.txt  cat output.txt bb|123456|12xx56

final solution

echo "aa | bb | cc | 12345678" \ | awk -f '|' '{gsub(/  */, "", $0)   #dbg print "length$4=" (length($4)-4)   masking=sprintf("%"(length($4)-4)"s", " ") ; gsub(/ /, "x", masking)   print $2  "|" $4 "|" substr($4, 1,2) masking substr($4,(length($4)-1),2) }'  bb|12345678|12xxxx78

i using echo "..." simplfy testing process. can take out, replace input.txt > output.txt , end of line , work before.

i've added (length($4)-1) make position of 2nd last char on $4 dynamic, based on length of ever word in $4.

ihth


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