pyqt - Python: How to share the same widget -


there qtabwidget 2 tabs: 'a' , 'b'.

and there listwidgeta = qtgui.qlistwidget() want share among 'a' , 'b'.

so far unable find way assign listwidgeta 2 different layouts. assigning 1 layout cancels assignment another. don't want create qtgui.qlistwidget() since produce lot of duplicate/repetitive code. here example. interesting know if there solution situation this.

from pyqt4 import qtgui, qtcore import sys, os   class dialog_01(qtgui.qmainwindow):     def __init__(self):         super(qtgui.qmainwindow,self).__init__()          mytabwidget = qtgui.qtabwidget()          qgroupboxa = qtgui.qgroupbox()         qhboxlayouta = qtgui.qhboxlayout()          qgroupboxa.setlayout(qhboxlayouta)         mytabwidget.addtab(qgroupboxa,' tab ')          listwidgeta = qtgui.qlistwidget()         in range(12):              qtgui.qlistwidgetitem( 'item '+str(i), listwidgeta )          qhboxlayouta.addwidget(listwidgeta)           qgroupboxb = qtgui.qgroupbox()         qhboxlayoutb = qtgui.qhboxlayout()         qgroupboxb.setlayout(qhboxlayoutb)          # qhboxlayoutb.addwidget(listwidgeta)            mytabwidget.addtab(qgroupboxb,' tab b ')          self.setcentralwidget(mytabwidget)  if __name__ == '__main__':     app = qtgui.qapplication(sys.argv)     dialog_1 = dialog_01()     dialog_1.show()     dialog_1.resize(480,320)     sys.exit(app.exec_())

as far know, each widget has exactely 1 parent.

you consider using 2 qlistview widgets (instead of qlistwidget) share 1 , 1 model. avoid concern duplicate/repetitive code.


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