python - Printing the values of a dictionary when its key is equal to the value of a list element -


i have code below , want print combo[values] combo[keys] in combo equal numb[i]

numb = [5, 7, 49, 11, 13]     combo  = {45 : (-1002,-1023), 49 : (-9999,-2347), 20 : (-1979, -1576), 13 : (-6000,-3450), 110     : (-2139, -8800), 7 : (-6754,-9087) }

how do it, please?

you mean loop through numb , print key if present?

two options; loop:

for key in numb:     if key in combo:         print combo[key]

which can expressed list comprehension too, produce list:

[combo[key] key in numb if key in combo]

or dictionary views:

for key in combo.viewkeys() & numb:     print combo[key]

again list comprehension too:

[combo[key] key in combo.viewkeys() & numb]

demo:

>>> numb = [5, 7, 49, 11, 13]     >>> combo  = {45 : (-1002,-1023), 49 : (-9999,-2347), 20 : (-1979, -1576), 13 : (-6000,-3450), 110     : (-2139, -8800), 7 : (-6754,-9087) } >>> [combo[key] key in numb if key in combo] [(-6754, -9087), (-9999, -2347), (-6000, -3450)] >>> [combo[key] key in combo.viewkeys() & numb] [(-9999, -2347), (-6000, -3450), (-6754, -9087)]

what route take depends on size of combo , numb, , on whether numb set well. if numb set, dict.viewkeys() optimize intersection operation using smaller of 2 , faster option, larger datasets.


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