bash - The variable is empty after inner loop `for` -

i know pipes proceeding in subshells, need little help.. got following code:

#!/bin/bash first="" second="" item1 in $(ls *.o)     first=`nm $item1 | grep -e '\<u\>' | awk '{print2}'`     item2 in $(ls *.o)             second=`nm $item2 | grep -e '\<t\>' | awk '{print3}'`          if [ "$first" == "$second" ];             echo "$item1 => $item2 ($second)"         else             echo "error!"         fi     done  done  

after script has been executed, i'm receiving empty $second (in brackets):

print_recursive.o => print_recursive.o () print_recursive.o => recfun.o () print_recursive.o => recursive.o () print_recursive.o => timeout.o () 

would mind rewrite code in right order? in advance.

always strive come minimal example. problem has nothing loops.

if have problem variable, check command sets it. in case:

second=`nm $item2 | grep -e '\<t\>' | awk '{print3}'` 

that awk command doesn't anything. guess meant {print $3}, though won't solve problem either, nm return multiple matching rows. want compare 2 sets? if so, sort them first.