random - Randomizing Numbers without repeating it in C# -


i want randomize 9 numbers random number in each trail different of number in previous attempt... here code

            random num1random = new random();         label1.text = num1random.next(1, 9).tostring();         label2.text = num1random.next(1, 9).tostring();         label3.text = num1random.next(1, 9).tostring();         label4.text = num1random.next(1, 9).tostring();         label5.text = num1random.next(1, 9).tostring();         label6.text = num1random.next(1, 9).tostring();         label7.text = num1random.next(1, 9).tostring();         label8.text = num1random.next(1, 9).tostring();         label9.text = num1random.next(1, 9).tostring();

you don't want 9 random numbers, really want numbers 1 9 in random order:

random r = new random(); var numbers = enumerable.range(1,9) // create sequence of integers 1 through 9     .orderby(x => r.next()) // randomize order     .toarray(); // turn sequence array.  // assign numbers labels label1.text = numbers[0]; ... label9.text = numbers[8];

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