python - Elementwise logical comparison of numpy arrays -


i have 2 numpy arrays of same shape. elements in arrays random integers [0,n]. need check (if any) of elements in same position in arrays equal.

the output need positions of same elements.

mock code:

a=np.array([0,1]) b=np.array([1,0]) c=np.array([1,1]) np.any_elemenwise(a,b) np.any_elemenwise(a,c) np.any_elemenwise(a,a)

desired output:

[] [1] [0,1]

i can write loop going through of elements 1 one, assume desired output can achieved faster.

edit:the question changed.

you want evaluate np.where(v1==v2)[0]


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