Serializing a function in python -


i trying serialize code , send json...

def f(x): return x*x def fi(x): return int(x[0])  code_string = marshal.dumps(fi.func_code)  jsn = {"code":code_string) json.dumps(jsn) # doesnt work if code_string fi

so... above code block works if function f(x)

but fails fi(x)

original exception was:

traceback (most recent call last):   file "/home/mohitdee/documents/python_scala/rdd.py", line 41, in <module>     send_data(json.dumps(jsn))   file "/usr/lib/python2.7/json/__init__.py", line 231, in dumps     return _default_encoder.encode(obj)   file "/usr/lib/python2.7/json/encoder.py", line 201, in encode     chunks = self.iterencode(o, _one_shot=true)   file "/usr/lib/python2.7/json/encoder.py", line 264, in iterencode     return _iterencode(o, 0) unicodedecodeerror: 'utf8' codec can't decode byte 0x83 in position 32: invalid start byte [48001 refs]

how resolve in python

marshall binary protocol, i.e. bunch of bytes custom interpretation. it's not text, doesn't conform in particular text encoding. is, part, sequence of bits. if absolutely need embed in text protocol json, need escape bytes don't make valid characters in relevant encoding (to safe, assume subset of ascii). canonical solution base64:

import base64  code_string = marshal.dumps(fi.func_code) code_base64 = base64.b64encode(code_string)  jsn = {"code": code_base64}

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